5x^2+7x-16=20-4x

Solution for 5x^2+7x-16=20-4x equation:

5x^2+7x-16=20-4x

We move all terms to the left:

5x^2+7x-16-(20-4x)=0

We add all the numbers together, and all the variables

5x^2+7x-(-4x+20)-16=0

We get rid of parentheses

5x^2+7x+4x-20-16=0

We add all the numbers together, and all the variables

5x^2+11x-36=0

a = 5; b = 11; c = -36;
Δ = b2-4ac
Δ = 112-4·5·(-36)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-29}{2*5}=\frac{-40}{10}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+29}{2*5}=\frac{18}{10}
=1+4/5
$